What is (x-1)^2+(y-6)^2=25 ?

The solution to (x-1)^2+(y-6)^2=25 is Circle with (a,b)=(1,6),r=5

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(x-1)^2+(y-6)^2=25

(x - 1)^{2} + (y - 6)^{2} = 25

(a, b) = (1, 6), r = 5

Solution steps

(x - 1)^{2} + (y - 6)^{2} = 25

Rewrite

(x - 1)^{2} + (y - 6)^{2} = 25

in the form of the standard circle equation

(x - 1)^{2} + (y - 6)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (1, 6), r = 5

\frac{x ^{2}}{64} + \frac{y ^{2}}{36} = 1

x^{2} + 4 y^{2} = 16

(x - 6)^{2} + (y + 5)^{2} = 16

4 x^{2} + 4 y^{2} = 25

x^{2} + y^{2} - 12 x - 10 y = - 12

What is (x-1)^2+(y-6)^2=25 ?
The solution to (x-1)^2+(y-6)^2=25 is Circle with (a,b)=(1,6),r=5