What is the axis x=y^2-4y+4 ?

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axis x=y^2-4y+4

axis

x = y^{2} - 4 y + 4

y = 2

Solution steps

x = y^{2} - 4 y + 4

Rewrite

x = y^{2} - 4 y + 4

in the standard form

4 \cdot \frac{1}{4} (x - 0) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (0, 2), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 2

(y + 9)^{2} = - 44 (x - 1)

y = 5 x^{2} + 4

y = 5 x^{2} + 3

x = + (y + 5)^{2} + 3

2 y = 4 x - x^{2}