What is the axis y+5x^2=4 ?

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axis y+5x^2=4

axis

y + 5 x^{2} = 4

x = 0

Solution steps

y + 5 x^{2} = 4

Rewrite

y + 5 x^{2} = 4

in the standard form:

4 (- \frac{1}{20}) (y - 4) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 4), p = - \frac{1}{20}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 2 x^{2} + 3

y^{2} - 8 x - 6 y - 23 = 0

y = (x - 5) (x - 1)

y = 2 x^{2} - 8 x + 3

y = - 16 x^{2} + 48 x + 100