What is the axis y=2x^2-7 ?

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axis y=2x^2-7

axis

y = 2 x^{2} - 7

x = 0

Solution steps

y = 2 x^{2} - 7

Rewrite

y = 2 x^{2} - 7

in the standard form:

4 \cdot \frac{1}{8} (y - (- 7)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 7), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

(x + 1)^{2} = 12 y

x = 2 (y - 5)^{2} + 3

x^{2} + 10 x = - 12 y - 1

2 y^{2} - 8 x - 24 y + 56 = 0

y = \frac{2 x ^{2} + 7 x + 12}{2}