What is the axis (y-1)^2=-6(x+2) ?

The axis (y-1)^2=-6(x+2) is y=1

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axis (y-1)^2=-6(x+2)

axis

(y - 1)^{2} = - 6 (x + 2)

y = 1

Solution steps

(y - 1)^{2} = - 6 (x + 2)

Rewrite

(y - 1)^{2} = - 6 (x + 2)

in the standard form:

4 (- \frac{3}{2}) (x - (- 2)) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (- 2, 1), p = - \frac{3}{2}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 1

y = 3 x^{2} + 12 x - 5

(x - 5)^{2} = 4 (y - 3)

x^{2} + 10 x + 21

y = - 4 x^{2} + 48 x

3 x^{2} = - 12 y