What is (2 2/5-1)\times 1/7 ?

The solution to (2 2/5-1)\times 1/7 is 1/5

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(2 2/5-1)\times 1/7

(2 \frac{2}{5} - 1) \cdot \frac{1}{7}

\frac{1}{5}

Solution steps

(2 \frac{2}{5} - 1) \cdot \frac{1}{7}

Convert mixed numbers to improper fractions:

2 \frac{2}{5} = \frac{12}{5}

2 \frac{2}{5}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{2}{5} = \frac{2 \cdot 5 + 2}{5}

= \frac{12}{5}

= (\frac{12}{5} - 1) \cdot \frac{1}{7}

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{12}{5} - 1) : \frac{7}{5}

\frac{12}{5} - 1

\frac{12}{5} - 1 = \frac{7}{5}

\frac{12}{5} - 1

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= - \frac{1 \cdot 5}{5} + \frac{12}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 5 + 12}{5}

- 1 \cdot 5 + 12 = 7

- 1 \cdot 5 + 12

Multiply the numbers:

1 \cdot 5 = 5

= - 5 + 12

Add/Subtract the numbers:

- 5 + 12 = 7

= 7

= \frac{7}{5}

= \frac{7}{5}

= \frac{7}{5} \cdot \frac{1}{7}

Multiply and divide (left to right)

\frac{7}{5} \cdot \frac{1}{7} : \frac{1}{5}

\frac{7}{5} \cdot \frac{1}{7}

\frac{7}{5} \cdot \frac{1}{7} = \frac{1}{5}

= \frac{1}{5}

= \frac{1}{5}

4 + 8 \times (- 5)

- 4 (3)^{2} + 11

(- 3)^{5} + 4 (- 3)^{4} + 8 (- 3)^{3} - 2 (- 3)^{2}

2 (3 - 4) - (- 3)^{2}

4 (- 4)^{2}