What is -1+2+3-6+4\div 2-1+1 ?

The solution to -1+2+3-6+4\div 2-1+1 is 0

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-1+2+3-6+4\div 2-1+1

- 1 + 2 + 3 - 6 + 4 \div 2 - 1 + 1

0

Solution steps

- 1 + 2 + 3 - 6 + 4 \div 2 - 1 + 1

Follow the PEMDAS order of operations

Multiply and divide (left to right)

4 \div 2 : 2

= - 1 + 2 + 3 - 6 + 2 - 1 + 1

Add and subtract (left to right)

- 1 + 2 + 3 - 6 + 2 - 1 + 1 : 0

= 0

\frac{3}{4} + \frac{1}{4}

\frac{3}{4} + \frac{1}{2}

\frac{1 1 ^{2} + 1 2 ^{2}}{( 2 + 3 )}

2 + (2 + 5 - 7)

8 (3)^{2} - 6