What is 4^2-8\div 2+(-3)^2 ?

The solution to 4^2-8\div 2+(-3)^2 is 21

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4^2-8\div 2+(-3)^2

4^{2} - 8 \div 2 + (- 3)^{2}

21

Solution steps

4^{2} - 8 \div 2 + (- 3)^{2}

Follow the PEMDAS order of operations

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 16 - 8 \div 2 + (- 3)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 16 - 8 \div 2 + 9

Multiply and divide (left to right)

8 \div 2 : 4

8 \div 2

8 \div 2 = 4

= 4

= 16 - 4 + 9

Add and subtract (left to right)

16 - 4 + 9 : 21

16 - 4 + 9

16 - 4 = 12

= 12 + 9

12 + 9 = 21

= 21

= 21

0 + 1 - 0 + 3

3 (3)^{2} - 6

136 + (- 150) - (- 14) + 0

3 3^{2} + 4 4^{2}

- 2 (- 1)^{2} - 5 (- 1) + 7