What is 10\times [3-2\times (5-4)-2\times (4-2)] ?

The solution to 10\times [3-2\times (5-4)-2\times (4-2)] is -30

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10\times [3-2\times (5-4)-2\times (4-2)]

10 \cdot [3 - 2 \cdot (5 - 4) - 2 \cdot (4 - 2)]

- 30

Solution steps

10 [3 - 2 (5 - 4) - 2 (4 - 2)]

Follow the PEMDAS order of operations

Calculate within parentheses

[3 - 2 \cdot (5 - 4) - 2 \cdot (4 - 2)] : - 3

= 10 (- 3)

Multiply and divide (left to right)

10 (- 3) : - 30

= - 30

(- 2 + 7)^{2} - 1 0^{2}

- 3 \times (- \frac{5}{9}) + (- 2)

6 \times 9 + 30 \div (- 3) + 19

8 \div (5 - 3)

6 (1)^{2} + 6 (1)

What is 10\times [3-2\times (5-4)-2\times (4-2)] ?
The solution to 10\times [3-2\times (5-4)-2\times (4-2)] is -30