What is 80\div 4-2(2+1)^2 ?

The solution to 80\div 4-2(2+1)^2 is 2

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80\div 4-2(2+1)^2

80 \div 4 - 2 (2 + 1)^{2}

2

Solution steps

80 \div 4 - 2 (2 + 1)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 1) : 3

2 + 1

2 + 1 = 3

= 3

= 80 \div 4 - 2 \cdot 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 80 \div 4 - 2 \cdot 9

Multiply and divide (left to right)

80 \div 4 : 20

80 \div 4

80 \div 4 = 20

= 20

= 20 - 2 \cdot 9

Multiply and divide (left to right)

2 \cdot 9 : 18

2 \cdot 9

2 \cdot 9 = 18

= 18

= 20 - 18

Add and subtract (left to right)

20 - 18 : 2

20 - 18

20 - 18 = 2

= 2

= 2

- 3 (- 1)^{3} - 4 (- 2)^{2}

- 4 {5 + 2 [5 + (- 8)]}

(- 3) \times 3 \times (- 3) \times (- 3) \times 3

9 - 15 + 4

3 \times (2 \times 4^{3}) \div 4