What is 3/7 (2)-5/14 (4) ?

The solution to 3/7 (2)-5/14 (4) is -4/7

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3/7 (2)-5/14 (4)

\frac{3}{7} (2) - \frac{5}{14} (4)

- \frac{4}{7}

Solution steps

\frac{3}{7} (2) - \frac{5}{14} (4)

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{3}{7} (2) : \frac{6}{7}

\frac{3}{7} (2)

Apply rule:

(a) = a

(2) = 2

= \frac{3}{7} \cdot 2

\frac{3}{7} \cdot 2 = \frac{6}{7}

\frac{3}{7} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= \frac{3}{7} \cdot \frac{2}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 2}{7 \cdot 1}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{6}{7 \cdot 1}

Multiply the numbers:

7 \cdot 1 = 7

= \frac{6}{7}

= \frac{6}{7}

= \frac{6}{7} - \frac{5}{14} (4)

Multiply and divide (left to right)

\frac{5}{14} (4) : \frac{10}{7}

\frac{5}{14} (4)

Apply rule:

(a) = a

(4) = 4

= \frac{5}{14} \cdot 4

\frac{5}{14} \cdot 4 = \frac{10}{7}

\frac{5}{14} \cdot 4

Convert element to fraction:

4 = \frac{4}{1}

= \frac{5}{14} \cdot \frac{4}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 \cdot 4}{14 \cdot 1}

Cancel

\frac{5 \cdot 4}{14 \cdot 1} : \frac{10}{7}

\frac{5 \cdot 4}{14 \cdot 1}

Multiply the numbers:

14 \cdot 1 = 14

= \frac{5 \cdot 4}{14}

Factor the number:

4 = 2 \cdot 2

= \frac{5 \cdot 2 \cdot 2}{14}

Factor the number:

14 = 2 \cdot 7

= \frac{5 \cdot 2 \cdot 2}{2 \cdot 7}

Cancel the common factor:

2

= \frac{5 \cdot 2}{7}

Multiply the numbers:

5 \cdot 2 = 10

= \frac{10}{7}

= \frac{10}{7}

= \frac{10}{7}

= \frac{6}{7} - \frac{10}{7}

Add and subtract (left to right)

\frac{6}{7} - \frac{10}{7} : - \frac{4}{7}

\frac{6}{7} - \frac{10}{7}

\frac{6}{7} - \frac{10}{7} = - \frac{4}{7}

\frac{6}{7} - \frac{10}{7}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{6 - 10}{7}

Subtract the numbers:

6 - 10 = - 4

= \frac{- 4}{7}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{7}

= - \frac{4}{7}

= - \frac{4}{7}

2^{2} - 3

2^{3} \times 3^{2}

- 4^{4} \times (- 2^{5})

(8 \times 1 0^{3})^{2}

2^{8} - 1