What is 77-(1+4-2)^2 ?

The solution to 77-(1+4-2)^2 is 68

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77-(1+4-2)^2

77 - (1 + 4 - 2)^{2}

68

Solution steps

77 - (1 + 4 - 2)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(1 + 4 - 2) : 3

= 77 - 3^{2}

Calculate exponents

3^{2} : 9

= 77 - 9

Add and subtract (left to right)

77 - 9 : 68

= 68

(4 - 5)^{3}

4 - 18 \div 6 + 1

12 \times (- 3 + 4) - 5 \times (- 6)

5 \times 4 + 30 \div 6 - 35 \div 7

\frac{( 0 - 1 ) ^{4}}{4}