What is (-2)^2-4(1)(-48) ?

The solution to (-2)^2-4(1)(-48) is 196

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(-2)^2-4(1)(-48)

(- 2)^{2} - 4 (1) (- 48)

196

Solution steps

(- 2)^{2} - 4 (1) (- 48)

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 - 4 (1) (- 48)

Multiply and divide (left to right)

4 (1) (- 48) : - 192

4 (1) (- 48)

4 (1) = 4

4 (1)

Apply rule:

(a) = a

(1) = 1

= 4 \cdot 1

Multiply the numbers:

4 \cdot 1 = 4

= 4

= 4 (- 48)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 48) = - 4 \cdot 48 = - 192

= - 192

= 4 - (- 192)

Add and subtract (left to right)

4 - (- 192) : 196

4 - (- 192)

Apply rule

- (- a) = + a

- (- 192) = + 192

= 4 + 192

4 + 192 = 196

= 196

= 196

\frac{1}{2} \times (- 2) + 2

- 2 [- 4 + (5 - 4 - 3) - (7 - 4 - 6 + 2)] - 4

[5 - 9 - 2] \times (- 3) + 10

(8 - 3 + 2)

- 4 (- 7 + 9) + 8