What is 4(2-5)^2\div 2+5-20 ?

The solution to 4(2-5)^2\div 2+5-20 is 3

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4(2-5)^2\div 2+5-20

4 (2 - 5)^{2} \div 2 + 5 - 20

3

Solution steps

4 (2 - 5)^{2} \div 2 + 5 - 20

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - 5) : - 3

2 - 5

2 - 5 = - 3

= - 3

= 4 (- 3)^{2} \div 2 + 5 - 20

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 4 \cdot 9 \div 2 + 5 - 20

Multiply and divide (left to right)

4 \cdot 9 \div 2 : 18

4 \cdot 9 \div 2

4 \cdot 9 = 36

= 36 \div 2

36 \div 2 = 18

= 18

= 18 + 5 - 20

Add and subtract (left to right)

18 + 5 - 20 : 3

18 + 5 - 20

18 + 5 = 23

= 23 - 20

23 - 20 = 3

= 3

= 3

4 - 8 + 8/4 + 25

[3 + 2 \times 6 [2 - 4 - (2 - 5)] - 8 \div 2]

2 (3/4) /3

2000 + 1900 \cdot 4

6 (6)^{2}