What is 17[53-(4+3)^2] ?

The solution to 17[53-(4+3)^2] is 68

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17[53-(4+3)^2]

17 [53 - (4 + 3)^{2}]

68

Solution steps

17 [53 - (4 + 3)^{2}]

Follow the PEMDAS order of operations

Calculate within parentheses

[53 - (4 + 3)^{2}] : 4

53 - (4 + 3)^{2}

Calculate within parentheses

(4 + 3) : 7

4 + 3

4 + 3 = 7

= 7

= 53 - 7^{2}

Calculate exponents

7^{2} : 49

7^{2}

7^{2} = 49

= 49

= 53 - 49

Add and subtract (left to right)

53 - 49 : 4

53 - 49

53 - 49 = 4

= 4

= 4

= 17 \cdot 4

Multiply and divide (left to right)

17 \cdot 4 : 68

17 \cdot 4

17 \cdot 4 = 68

= 68

= 68

90 + (30% \times 90)

7 \times 4 - 3

9^{3} + 9^{3} + 9^{3} + 9^{3} + 9^{3} + 9^{3}

\frac{2}{5} + \frac{3}{5}

1 6^{2} \times 2