What is (3^3+3^2)/(3^4) ?

The solution to (3^3+3^2)/(3^4) is 4/9

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(3^3+3^2)/(3^4)

\frac{3 ^{3} + 3 ^{2}}{3 ^{4}}

\frac{4}{9}

Solution steps

\frac{3 ^{3} + 3 ^{2}}{3 ^{4}}

Solve

3^{3} + 3^{2} : 36

Follow the PEMDAS order of operations

Calculate exponents

3^{3} : 27

3^{3}

3^{3} = 27

= 27

= 27 + 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 27 + 9

Add and subtract (left to right)

27 + 9 : 36

27 + 9

27 + 9 = 36

= 36

= 36

Solve

3^{4} : 81

3^{4} = 81

= 81

= \frac{36}{81}

Cancel the common factor:

9

= \frac{4}{9}

\frac{5 3 ^{2} - 2 7 ^{2}}{7 9 ^{2} - 5 1 ^{2}}

4^{2} - 2

2 \times 3^{2}

12 \div 3 (5 - 1)

4 (- 1)^{3}