What is 6 3/4+(4 2/4+5 1/4) ?

The solution to 6 3/4+(4 2/4+5 1/4) is 16 1/2

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6 3/4+(4 2/4+5 1/4)

6 \frac{3}{4} + (4 \frac{2}{4} + 5 \frac{1}{4})

16 \frac{1}{2}

Solution steps

6 \frac{3}{4} + (4 \frac{2}{4} + 5 \frac{1}{4})

Convert mixed numbers to improper fractions:

6 \frac{3}{4} = \frac{27}{4}

= \frac{27}{4} + (4 \frac{2}{4} + 5 \frac{1}{4})

Convert mixed numbers to improper fractions:

4 \frac{2}{4} = \frac{18}{4}

= \frac{27}{4} + (\frac{18}{4} + 5 \frac{1}{4})

Convert mixed numbers to improper fractions:

5 \frac{1}{4} = \frac{21}{4}

= \frac{27}{4} + (\frac{18}{4} + \frac{21}{4})

\frac{18}{4} = \frac{9}{2}

= \frac{27}{4} + \frac{9}{2} + \frac{21}{4}

Follow the PEMDAS order of operations

Add and subtract (left to right)

\frac{27}{4} + \frac{9}{2} + \frac{21}{4} : \frac{33}{2}

= \frac{33}{2}

Convert improper fractions to mixed numbers:

\frac{33}{2} = 16 \frac{1}{2}

= 16 \frac{1}{2}

\frac{2}{27} (3^{7} - 8 \cdot 7 + 2)

16 + (- 18) - 24 + 45

2^{4} \cdot 5

2^{2} - 2 (2) - 8

- 2^{2} + 8 + 5