What is 8/((2+2)^3) ?

The solution to 8/((2+2)^3) is 1/8

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8/((2+2)^3)

\frac{8}{( 2 + 2 ) ^{3}}

\frac{1}{8}

Solution steps

\frac{8}{( 2 + 2 ) ^{3}}

Solve

(2 + 2)^{3} : 64

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 2) : 4

2 + 2

2 + 2 = 4

= 4

= 4^{3}

Calculate exponents

4^{3} : 64

4^{3}

4^{3} = 64

= 64

= 64

= \frac{8}{64}

Cancel the common factor:

8

= \frac{1}{8}

2 (0) - 7

- 4 - (- 6 - 12) - (- (- 8 - 3) + (- (- 1 + 7) - 8)) - 10

2 (15) + 8

81 \div 9 \times 5 - 3^{3} + 2 - 5^{2}

(- 2)^{3} + 4 (- 2) + 7