What is (-3)^2+4(-3)+3 ?

The solution to (-3)^2+4(-3)+3 is 0

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(-3)^2+4(-3)+3

(- 3)^{2} + 4 (- 3) + 3

0

Solution steps

(- 3)^{2} + 4 (- 3) + 3

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 + 4 (- 3) + 3

Multiply and divide (left to right)

4 (- 3) : - 12

4 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 3) = - 4 \cdot 3 = - 12

= - 12

= 9 - 12 + 3

Add and subtract (left to right)

9 - 12 + 3 : 0

9 - 12 + 3

9 - 12 = - 3

= - 3 + 3

- 3 + 3 = 0

= 0

= 0

\frac{1}{2} (4 + 5)^{2}

\frac{1}{2} \times 3 \times (5 + 7)

- (- 3) + (- 4) + 5 + (- 2)

2 (2 - (- 3 + 6)) - 3

\frac{3}{4} (2)^{3}