What is 7(2)-3(2^2-(6(8)\div (2^2))) ?

The solution to 7(2)-3(2^2-(6(8)\div (2^2))) is 38

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7(2)-3(2^2-(6(8)\div (2^2)))

7 (2) - 3 (2^{2} - (6 (8) \div (2^{2})))

38

Solution steps

7 (2) - 3 (2^{2} - (6 (8) \div (2^{2})))

Follow the PEMDAS order of operations

Calculate within parentheses

(2^{2} - (6 (8) \div (2^{2}))) : - 8

2^{2} - (6 (8) \div (2^{2}))

Calculate within parentheses

(6 (8) \div (2^{2})) : 12

6 (8) \div (2^{2})

Calculate within parentheses

(2^{2}) : 4

2^{2}

2^{2} = 4

= 4

= 6 (8) \div 4

Multiply and divide (left to right)

6 (8) \div 4 : 12

6 (8) \div 4

6 (8) = 48

6 (8)

Apply rule:

(a) = a

(8) = 8

= 6 \cdot 8

Multiply the numbers:

6 \cdot 8 = 48

= 48

= 48 \div 4

48 \div 4 = 12

= 12

= 12

= 2^{2} - 12

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 - 12

Add and subtract (left to right)

4 - 12 : - 8

4 - 12

4 - 12 = - 8

= - 8

= - 8

= 7 (2) - 3 (- 8)

Multiply and divide (left to right)

7 (2) : 14

7 (2)

Apply rule:

(a) = a

(2) = 2

= 7 \cdot 2

Multiply the numbers:

7 \cdot 2 = 14

= 14

= 14 - 3 (- 8)

Multiply and divide (left to right)

3 (- 8) : - 24

3 (- 8)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 8) = - 3 \cdot 8 = - 24

= - 24

= 14 - (- 24)

Add and subtract (left to right)

14 - (- 24) : 38

14 - (- 24)

Apply rule

- (- a) = + a

- (- 24) = + 24

= 14 + 24

14 + 24 = 38

= 38

= 38

2 (3) - 2

2 \cdot 3^{6}

- 5 + (- 5)^{2}

(- 5)^{3} + (- 3)^{4} - (- 2)^{5} + (- 4)^{2}

10 \times 6 + 7 + 2 \times 4^{2}

What is 7(2)-3(2^2-(6(8)\div (2^2))) ?
The solution to 7(2)-3(2^2-(6(8)\div (2^2))) is 38