What is 9^2-(5+2*6^2) ?

The solution to 9^2-(5+2*6^2) is 4

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9^2-(5+2*6^2)

9^{2} - (5 + 2 \cdot 6^{2})

4

Solution steps

9^{2} - (5 + 2 \cdot 6^{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(5 + 2 \cdot 6^{2}) : 77

5 + 2 \cdot 6^{2}

Calculate exponents

6^{2} : 36

6^{2}

6^{2} = 36

= 36

= 5 + 2 \cdot 36

Multiply and divide (left to right)

2 \cdot 36 : 72

2 \cdot 36

2 \cdot 36 = 72

= 72

= 5 + 72

Add and subtract (left to right)

5 + 72 : 77

5 + 72

5 + 72 = 77

= 77

= 77

= 9^{2} - 77

Calculate exponents

9^{2} : 81

9^{2}

9^{2} = 81

= 81

= 81 - 77

Add and subtract (left to right)

81 - 77 : 4

81 - 77

81 - 77 = 4

= 4

= 4

5 \times 4 - 3 (5 - 6 + 4 \div 2)

- 6 - (9 - 2)^{2} + (- 9)^{2} - (2)

[21 \div (7 \cdot 3)] + 4 (5 - 1)

- (- 1)^{2} - 2 (- 1)

- (2)^{2} + 3 (2) - 2