What is (2^3+3^0)/(3^3-3) ?

The solution to (2^3+3^0)/(3^3-3) is 3/8

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(2^3+3^0)/(3^3-3)

\frac{2 ^{3} + 3 ^{0}}{3 ^{3} - 3}

\frac{3}{8}

Solution steps

\frac{2 ^{3} + 3 ^{0}}{3 ^{3} - 3}

Solve

2^{3} + 3^{0} : 9

Follow the PEMDAS order of operations

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 + 3^{0}

Calculate exponents

3^{0} : 1

3^{0}

3^{0} = 1

= 1

= 8 + 1

Add and subtract (left to right)

8 + 1 : 9

8 + 1

8 + 1 = 9

= 9

= 9

Solve

3^{3} - 3 : 24

Follow the PEMDAS order of operations

Calculate exponents

3^{3} : 27

3^{3}

3^{3} = 27

= 27

= 27 - 3

Add and subtract (left to right)

27 - 3 : 24

27 - 3

27 - 3 = 24

= 24

= 24

= \frac{9}{24}

Cancel the common factor:

3

= \frac{3}{8}

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