What is (4)+(5)(2)+(40)\div (10)-7 ?

The solution to (4)+(5)(2)+(40)\div (10)-7 is 11

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(4)+(5)(2)+(40)\div (10)-7

(4) + (5) (2) + (40) \div (10) - 7

11

Solution steps

(4) + (5) (2) + (40) \div (10) - 7

Follow the PEMDAS order of operations

Multiply and divide (left to right)

(5) (2) : 10

= (4) + 10 + (40) \div (10) - 7

Multiply and divide (left to right)

(40) \div (10) : \frac{( 40 )}{( 10 )}

= (4) + 10 + \frac{( 40 )}{( 10 )} - 7

Add and subtract (left to right)

(4) + 10 + \frac{( 40 )}{( 10 )} - 7 : 11

= 11

- 3 (8 - 30)

4 + 4^{2} \div 2

\frac{9}{7 ^{2} - 16}

3 (- 1) + 6

(- 2)^{2} + 8

What is (4)+(5)(2)+(40)\div (10)-7 ?
The solution to (4)+(5)(2)+(40)\div (10)-7 is 11