What is 41/21*45/23*49/25*53/27 ?

The solution to 41/21*45/23*49/25*53/27 is 14 721/1035

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41/2145/2349/25*53/27

41/21 \cdot 45/23 \cdot 49/25 \cdot 53/27

14 \frac{721}{1035}

Solution steps

41/21 \cdot 45/23 \cdot 49/25 \cdot 53/27

Follow the PEMDAS order of operations

Multiply and divide (left to right)

41/21 = \frac{41}{21}

= \frac{41}{21} \cdot 45/23 \cdot 49/25 \cdot 53/27

\frac{41}{21} \cdot 45 = \frac{615}{7}

= \frac{615}{7} /23 \cdot 49/25 \cdot 53/27

\frac{615}{7} /23 = \frac{615}{161}

= \frac{615}{161} \cdot 49/25 \cdot 53/27

\frac{615}{161} \cdot 49 = \frac{4305}{23}

= \frac{4305}{23} /25 \cdot 53/27

\frac{4305}{23} /25 = \frac{861}{115}

= \frac{861}{115} \cdot 53/27

\frac{861}{115} \cdot 53 = \frac{45633}{115}

= \frac{45633}{115} /27

\frac{45633}{115} /27 = \frac{15211}{1035}

= \frac{15211}{1035}

Convert improper fractions to mixed numbers:

\frac{15211}{1035} = 14 \frac{721}{1035}

= 14 \frac{721}{1035}

(3^{2} - 2^{2})^{2}

6 - 5 (12 - 22)

3^{2} + (- 8)^{2}

- 1 - 3 - 4 - 4 - 2

2 - 3 \div 9

What is 41/21*45/23*49/25*53/27 ?
The solution to 41/21*45/23*49/25*53/27 is 14 721/1035