What is ((4-1)^2)/(3+4) ?

The solution to ((4-1)^2)/(3+4) is 1 2/7

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((4-1)^2)/(3+4)

\frac{( 4 - 1 ) ^{2}}{3 + 4}

1 \frac{2}{7}

Solution steps

\frac{( 4 - 1 ) ^{2}}{3 + 4}

Solve

(4 - 1)^{2} : 9

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - 1) : 3

4 - 1

4 - 1 = 3

= 3

= 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9

Solve

3 + 4 : 7

3 + 4 = 7

= 7

= \frac{9}{7}

Convert improper fractions to mixed numbers:

\frac{9}{7} = 1 \frac{2}{7}

\frac{9}{7} = 1

Remainder

2

\frac{9}{7}

Write the problem in long division format

7 \overline{∣ 9}

Divide

9

7

to get

1

Divide

9

7

to get

1

1 7 \overline{∣ 9}

Multiply the quotient digit

(1)

by the divisor

7

1 7 \overline{∣ 9} \underline{7}

Subtract

7

from

9

1 7 \overline{∣ 9} \underline{7} 2

1 7 \overline{∣ 9} \underline{7} 2

The solution for Long Division of

\frac{9}{7}

1

with remainder of

2

1 Remainder 2

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{9}{7} = 1 \frac{2}{7}

= 1 \frac{2}{7}

= 1 \frac{2}{7}

\frac{1}{2} (- 2)^{2}

12 + 15 \div 3 \times 6 - 4

6 \div 2 \times (2 + 1)

2^{2} + 4

3 + \frac{1}{2} - \frac{3}{4}