What is 40-(10/32 \times 50) ?

The solution to 40-(10/32 \times 50) is 24 3/8

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40-(10/32 \times 50)

40 - (\frac{10}{32} \cdot 50)

24 \frac{3}{8}

Solution steps

40 - (\frac{10}{32} \cdot 50)

\frac{10}{32} = \frac{5}{16}

= 40 - \frac{5}{16} \cdot 50

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{5}{16} \cdot 50 : \frac{125}{8}

= 40 - \frac{125}{8}

Add and subtract (left to right)

40 - \frac{125}{8} : \frac{195}{8}

= \frac{195}{8}

Convert improper fractions to mixed numbers:

\frac{195}{8} = 24 \frac{3}{8}

= 24 \frac{3}{8}

\frac{8 - 3 ^{2} + 32 - 3 + 32}{4 - 3 ^{2} - 4}

\frac{2 ( 4 )}{1 + 2 ^{2} + 1 ^{2}}

(60 - \frac{1}{8}) + (30 - \frac{1}{16})

14 [31 - (3 + 2)^{2}]

4 \cdot (- 2^{2}) + 1