What is -(-1)^2+2\times 2^2-4 ?

The solution to -(-1)^2+2\times 2^2-4 is 3

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-(-1)^2+2\times 2^2-4

- (- 1)^{2} + 2 \cdot 2^{2} - 4

3

Solution steps

- (- 1)^{2} + 2 \cdot 2^{2} - 4

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 1 + 2 \cdot 2^{2} - 4

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= - 1 + 2 \cdot 4 - 4

Multiply and divide (left to right)

2 \cdot 4 : 8

2 \cdot 4

2 \cdot 4 = 8

= 8

= - 1 + 8 - 4

Add and subtract (left to right)

- 1 + 8 - 4 : 3

- 1 + 8 - 4

- 1 + 8 = 7

= 7 - 4

7 - 4 = 3

= 3

= 3

(2)^{2} - 6 (2) + 3

180 - 76 - 34

- 3 (6)^{2}

10 \cdot \frac{1}{3} \div \frac{25}{6}

15 - 3 \times 12 \div 6 + 42 \div 8