What is (5(1)^2+20(1)+50)\div ((1+2)^2) ?

The solution to (5(1)^2+20(1)+50)\div ((1+2)^2) is 8 1/3

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Popular >

(5(1)^2+20(1)+50)\div ((1+2)^2)

Solution

(5 (1)^{2} + 20 (1) + 50) \div ((1 + 2)^{2})

Solution

8 \frac{1}{3}

Solution steps

(5 (1)^{2} + 20 (1) + 50) \div ((1 + 2)^{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(5 (1)^{2} + 20 (1) + 50) : 75

5 (1)^{2} + 20 (1) + 50

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 5 \cdot 1 + 20 (1) + 50

Multiply and divide (left to right)

5 \cdot 1 : 5

5 \cdot 1

5 \cdot 1 = 5

= 5

= 5 + 20 (1) + 50

Multiply and divide (left to right)

20 (1) : 20

20 (1)

Apply rule:

(a) = a

(1) = 1

= 20 \cdot 1

Multiply the numbers:

20 \cdot 1 = 20

= 20

= 5 + 20 + 50

Add and subtract (left to right)

5 + 20 + 50 : 75

5 + 20 + 50

5 + 20 = 25

= 25 + 50

25 + 50 = 75

= 75

= 75

= 75 \div ((1 + 2)^{2})

Calculate within parentheses

((1 + 2)^{2}) : 9

(1 + 2)^{2}

Calculate within parentheses

(1 + 2) : 3

1 + 2

1 + 2 = 3

= 3

= 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9

= 75 \div 9

Multiply and divide (left to right)

75 \div 9 : \frac{75}{9}

75 \div 9

75 \div 9 = \frac{75}{9}

= \frac{75}{9}

= \frac{75}{9}

Simplify

\frac{75}{9} : 8 \frac{1}{3}

Cancel the common factor:

3

= \frac{25}{3}

Convert improper fractions to mixed numbers:

\frac{25}{3} = 8 \frac{1}{3}

\frac{25}{3} = 8

Remainder

1

\frac{25}{3}

Write the problem in long division format

3 \overline{∣ 25}

Divide

25

3

to get

8

Divide

25

3

to get

8

8 3 \overline{∣ 25}

Multiply the quotient digit

(8)

by the divisor

3

8 3 \overline{∣ 25} \underline{24}

Subtract

24

from

25

8 3 \overline{∣ 25} \underline{24} 1

8 3 \overline{∣ 25} \underline{24} 1

The solution for Long Division of

\frac{25}{3}

8

with remainder of

1

8 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{25}{3} = 8 \frac{1}{3}

= 8 \frac{1}{3}

= 8 \frac{1}{3}

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4 (- 3)^{2} - 3 (- 3) + 4

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8 - 12 + 5

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- \frac{2}{3} (3) + 4

0^2+10

0^{2} + 10

2^3-3(2)^2

2^{3} - 3 (2)^{2}

Frequently Asked Questions (FAQ)

What is (5(1)^2+20(1)+50)\div ((1+2)^2) ?
The solution to (5(1)^2+20(1)+50)\div ((1+2)^2) is 8 1/3