What is 4(2)^2-7(2)+4 ?

The solution to 4(2)^2-7(2)+4 is 6

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4(2)^2-7(2)+4

4 (2)^{2} - 7 (2) + 4

6

Solution steps

4 (2)^{2} - 7 (2) + 4

Follow the PEMDAS order of operations

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= 4 \cdot 4 - 7 (2) + 4

Multiply and divide (left to right)

4 \cdot 4 : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 16 - 7 (2) + 4

Multiply and divide (left to right)

7 (2) : 14

7 (2)

Apply rule:

(a) = a

(2) = 2

= 7 \cdot 2

Multiply the numbers:

7 \cdot 2 = 14

= 14

= 16 - 14 + 4

Add and subtract (left to right)

16 - 14 + 4 : 6

16 - 14 + 4

16 - 14 = 2

= 2 + 4

2 + 4 = 6

= 6

= 6

- 5 - 14 - 5 - 2 - 3 - 4 - 2 - 5 - 17

140 \div (- 7 + (- 21))

5 (2)^{3} + 6 (2)

12 + 9^{2} \div 3

(- 18 + 12) \div 6