What is (-3)^2+4(-3)+1 ?

The solution to (-3)^2+4(-3)+1 is -2

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(-3)^2+4(-3)+1

(- 3)^{2} + 4 (- 3) + 1

- 2

Solution steps

(- 3)^{2} + 4 (- 3) + 1

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 + 4 (- 3) + 1

Multiply and divide (left to right)

4 (- 3) : - 12

4 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 3) = - 4 \cdot 3 = - 12

= - 12

= 9 - 12 + 1

Add and subtract (left to right)

9 - 12 + 1 : - 2

9 - 12 + 1

9 - 12 = - 3

= - 3 + 1

- 3 + 1 = - 2

= - 2

= - 2

(7 \times 7 + 5) \div (18 - 15 \div 3 + 5) \times 2

(- 13) + (- 12) + (- 11)

- 2 (- 1)^{2} - 4 (- 1) - 3

- 5 + 12 - 11 + 6 + 2 + 7

5^{3} \cdot 2 + 2^{3} 5^{3}