What is (-150)\div (+5)\times (19-21) ?

The solution to (-150)\div (+5)\times (19-21) is 60

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(-150)\div (+5)\times (19-21)

(- 150) \div (+ 5) \times (19 - 21)

60

Solution steps

(- 150) \div (5) \times (19 - 21)

Follow the PEMDAS order of operations

Calculate within parentheses

(19 - 21) : - 2

= (- 150) \div (5) \times (- 2)

Multiply and divide (left to right)

(- 150) \div (5) \times (- 2) : 60

= 60

(2 \cdot 1 + 3)^{2}

3 + 5 (- 7 - 3)

\frac{5 + 4}{4 ( - 2 ) + 8}

2 8^{2} + 1 8^{2}

\frac{4 ( 3 ) ^{2} - 1}{3 ^{2}}

What is (-150)\div (+5)\times (19-21) ?
The solution to (-150)\div (+5)\times (19-21) is 60