What is (13^2-12^2)^2+(6^2+7^4)^0 ?

The solution to (13^2-12^2)^2+(6^2+7^4)^0 is 626

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(13^2-12^2)^2+(6^2+7^4)^0

(1 3^{2} - 1 2^{2})^{2} + (6^{2} + 7^{4})^{0}

626

Solution steps

(1 3^{2} - 1 2^{2})^{2} + (6^{2} + 7^{4})^{0}

Follow the PEMDAS order of operations

Calculate within parentheses

(1 3^{2} - 1 2^{2}) : 25

= 2 5^{2} + (6^{2} + 7^{4})^{0}

Calculate within parentheses

(6^{2} + 7^{4}) : 2437

= 2 5^{2} + 243 7^{0}

Calculate exponents

2 5^{2} : 625

= 625 + 243 7^{0}

Calculate exponents

243 7^{0} : 1

= 625 + 1

Add and subtract (left to right)

625 + 1 : 626

= 626

16 - 3 + 4 + 2 - 2

3 - (4 \cdot 7 - 9) + (3 - 7 + 4) 2 - 1

(21 \div 4) \times (13 \div 4) \times (15 \div 4)

4^{2} \cdot 8

- (- 20) (3) + (- 72) \div 8

What is (13^2-12^2)^2+(6^2+7^4)^0 ?
The solution to (13^2-12^2)^2+(6^2+7^4)^0 is 626