What is 4^2\div 4-3 ?

The solution to 4^2\div 4-3 is 1

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4^2\div 4-3

4^{2} \div 4 - 3

1

Solution steps

4^{2} \div 4 - 3

Follow the PEMDAS order of operations

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 16 \div 4 - 3

Multiply and divide (left to right)

16 \div 4 : 4

16 \div 4

16 \div 4 = 4

= 4

= 4 - 3

Add and subtract (left to right)

4 - 3 : 1

4 - 3

4 - 3 = 1

= 1

= 1

(3072 \div 5) - (512 \div 12)

[3 + [3 (4 - 5) - 2 \cdot 2] - 6] - [2 (2 - 5) + 1]

9 + 3 (2^{2} - 1) \div 3 \times 5 - 14

4 \times (\times (- 3)) + 5 (3)

(30 - 3) \times (2 \div 9) + 8