What is 1^2-4\times 1+3 ?

The solution to 1^2-4\times 1+3 is 0

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1^2-4\times 1+3

1^{2} - 4 \cdot 1 + 3

0

Solution steps

1^{2} - 4 \cdot 1 + 3

Follow the PEMDAS order of operations

Calculate exponents

1^{2} : 1

= 1 - 4 \cdot 1 + 3

Multiply and divide (left to right)

4 \cdot 1 : 4

= 1 - 4 + 3

Add and subtract (left to right)

1 - 4 + 3 : 0

= 0

(+ 9) + (- 14) + (+ 33) + (- 45) + (- 23)

10 (8 \times (- 1))

1 - (- 8) - \frac{12}{- 3}

1/2 + 3/5 + 1/4

1 \times 1 + 2 \times (- \frac{1}{2}) + 3 \times 0