What is 4+1/5-6(7-4/2) ?

The solution to 4+1/5-6(7-4/2) is -129/5

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4+1/5-6(7-4/2)

4 + \frac{1}{5} - 6 (7 - \frac{4}{2})

- \frac{129}{5}

Solution steps

4 + \frac{1}{5} - 6 (7 - \frac{4}{2})

\frac{4}{2} = 2

Divide the numbers:

\frac{4}{2} = 2

2

= 4 + \frac{1}{5} - 6 (7 - 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(7 - 2) : 5

7 - 2

7 - 2 = 5

= 5

= 4 + \frac{1}{5} - 6 \cdot 5

Multiply and divide (left to right)

6 \cdot 5 : 30

6 \cdot 5

6 \cdot 5 = 30

= 30

= 4 + \frac{1}{5} - 30

Add and subtract (left to right)

4 + \frac{1}{5} - 30 : - \frac{129}{5}

4 + \frac{1}{5} - 30

4 + \frac{1}{5} = \frac{21}{5}

4 + \frac{1}{5}

Convert element to fraction:

4 = \frac{4 \cdot 5}{5}

= \frac{4 \cdot 5}{5} + \frac{1}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 5 + 1}{5}

4 \cdot 5 + 1 = 21

4 \cdot 5 + 1

Multiply the numbers:

4 \cdot 5 = 20

= 20 + 1

Add the numbers:

20 + 1 = 21

= 21

= \frac{21}{5}

= \frac{21}{5} - 30

\frac{21}{5} - 30 = - \frac{129}{5}

\frac{21}{5} - 30

Convert element to fraction:

30 = \frac{30 \cdot 5}{5}

= - \frac{30 \cdot 5}{5} + \frac{21}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 30 \cdot 5 + 21}{5}

- 30 \cdot 5 + 21 = - 129

- 30 \cdot 5 + 21

Multiply the numbers:

30 \cdot 5 = 150

= - 150 + 21

Add/Subtract the numbers:

- 150 + 21 = - 129

= - 129

= \frac{- 129}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{129}{5}

= - \frac{129}{5}

= - \frac{129}{5}

(- 20)^{2} + 8 (- 20)

2 (- 2)^{2} + 4

72 \div (7 - 1) \cdot 3

- 15 + 7 + 8 - 5 - 6 - 4 + 11 - 3

4 (3) + 5 (4)^{2} - 3 (2)