The solution to 8/3-2-4 is -10/3

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8/3-2-4

Solution

\frac{8}{3} - 2 - 4

- \frac{10}{3}

Solution steps

\frac{8}{3} - 2 - 4

Follow the PEMDAS order of operations

Add and subtract (left to right)

\frac{8}{3} - 2 = \frac{2}{3}

\frac{8}{3} - 2

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= - \frac{2 \cdot 3}{3} + \frac{8}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 \cdot 3 + 8}{3}

- 2 \cdot 3 + 8 = 2

- 2 \cdot 3 + 8

Multiply the numbers:

2 \cdot 3 = 6

= - 6 + 8

Add/Subtract the numbers:

- 6 + 8 = 2

= 2

= \frac{2}{3}

= \frac{2}{3} - 4

\frac{2}{3} - 4 = - \frac{10}{3}

\frac{2}{3} - 4

Convert element to fraction:

4 = \frac{4 \cdot 3}{3}

= - \frac{4 \cdot 3}{3} + \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 4 \cdot 3 + 2}{3}

- 4 \cdot 3 + 2 = - 10

- 4 \cdot 3 + 2

Multiply the numbers:

4 \cdot 3 = 12

= - 12 + 2

Add/Subtract the numbers:

- 12 + 2 = - 10

= - 10

= \frac{- 10}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{10}{3}

= - \frac{10}{3}

4 + 48 - 3 \times 3

- 2 (- 4) + 4

6^{2} + 10 \times (9 \div 3)

2 (- 6) (9) - 3 (\frac{1}{3}) (\frac{2}{4})

- 3 (3) + 2 (4)