What is (2(-2))/((-2)^2+1) ?

The solution to (2(-2))/((-2)^2+1) is -4/5

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(2(-2))/((-2)^2+1)

\frac{2 ( - 2 )}{( - 2 ) ^{2} + 1}

- \frac{4}{5}

Solution steps

\frac{2 ( - 2 )}{( - 2 ) ^{2} + 1}

Solve

2 (- 2) : - 4

2 (- 2) = - 4

= - 4

Solve

(- 2)^{2} + 1 : 5

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 + 1

Add and subtract (left to right)

4 + 1 : 5

4 + 1

4 + 1 = 5

= 5

= 5

= \frac{- 4}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{5}

12 (2)^{2} + 6 (2) - 6

4 (4 + 5)

5 - (- \frac{1}{2}) + \frac{2}{3}

2 (3)^{2} - 12 (3) + 13

(3 + 6^{2}) \div 3 \cdot 2^{2}