What is (2+0-7-7-5-7-5+1+2-5)/(10) ?

The solution to (2+0-7-7-5-7-5+1+2-5)/(10) is -3 1/10

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(2+0-7-7-5-7-5+1+2-5)/(10)

\frac{2 + 0 - 7 - 7 - 5 - 7 - 5 + 1 + 2 - 5}{10}

- 3 \frac{1}{10}

Solution steps

\frac{2 + 0 - 7 - 7 - 5 - 7 - 5 + 1 + 2 - 5}{10}

Solve

2 + 0 - 7 - 7 - 5 - 7 - 5 + 1 + 2 - 5 : - 31

Follow the PEMDAS order of operations

Add and subtract (left to right)

2 + 0 = 2

= 2 - 7 - 7 - 5 - 7 - 5 + 1 + 2 - 5

2 - 7 = - 5

= - 5 - 7 - 5 - 7 - 5 + 1 + 2 - 5

- 5 - 7 = - 12

= - 12 - 5 - 7 - 5 + 1 + 2 - 5

- 12 - 5 = - 17

= - 17 - 7 - 5 + 1 + 2 - 5

- 17 - 7 = - 24

= - 24 - 5 + 1 + 2 - 5

- 24 - 5 = - 29

= - 29 + 1 + 2 - 5

- 29 + 1 = - 28

= - 28 + 2 - 5

- 28 + 2 = - 26

= - 26 - 5

- 26 - 5 = - 31

= - 31

= \frac{- 31}{10}

Simplify

\frac{- 31}{10} : - 3 \frac{1}{10}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{31}{10}

Convert improper fractions to mixed numbers:

\frac{31}{10} = 3 \frac{1}{10}

\frac{31}{10} = 3

Remainder

1

\frac{31}{10}

Write the problem in long division format

10 \overline{∣ 31}

Divide

31

10

to get

3

Divide

31

10

to get

3

3 10 \overline{∣ 31}

Multiply the quotient digit

(3)

by the divisor

10

3 10 \overline{∣ 31} \underline{30}

Subtract

30

from

31

3 10 \overline{∣ 31} \underline{30} 1

3 10 \overline{∣ 31} \underline{30} 1

The solution for Long Division of

\frac{31}{10}

3

with remainder of

1

3 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{31}{10} = 3 \frac{1}{10}

= 3 \frac{1}{10}

= - 3 \frac{1}{10}

= - 3 \frac{1}{10}

8 + (- 25) + 16 (- 25) - 16

\frac{6 \cdot ( - 2 + 1 )}{- 2}

- 3 (0 - 2)^{2} + 18

5 \times 5 - 4 \times 5 (12 - 2^{2}) + 2 + 10 \div 2

51 - 6 (2) - 14 \div 7 - 5

What is (2+0-7-7-5-7-5+1+2-5)/(10) ?
The solution to (2+0-7-7-5-7-5+1+2-5)/(10) is -3 1/10