What is 40\div [2+2\times (19-16)] ?

The solution to 40\div [2+2\times (19-16)] is 5

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40\div [2+2\times (19-16)]

40 \div [2 + 2 \times (19 - 16)]

5

Solution steps

40 \div [2 + 2 \times (19 - 16)]

Follow the PEMDAS order of operations

Calculate within parentheses

[2 + 2 \times (19 - 16)] : 8

= 40 \div 8

Multiply and divide (left to right)

40 \div 8 : 5

= 5

4 (- 4) + 6

81 (4) - (4)^{5}

\frac{2 ( 8 ) ^{2} - 12 ( 8 ) - 32}{8 ^{2} - 64}

- (10)^{3} + 3 (10)^{2} + 240 (10) + 5139

(- 3) - 19 + 15

What is 40\div [2+2\times (19-16)] ?
The solution to 40\div [2+2\times (19-16)] is 5