What is (5/3-1)+(7/2-2) ?

The solution to (5/3-1)+(7/2-2) is 2 1/6

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(5/3-1)+(7/2-2)

(\frac{5}{3} - 1) + (\frac{7}{2} - 2)

2 \frac{1}{6}

Solution steps

(\frac{5}{3} - 1) + (\frac{7}{2} - 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{5}{3} - 1) : \frac{2}{3}

= \frac{2}{3} + (\frac{7}{2} - 2)

Calculate within parentheses

(\frac{7}{2} - 2) : \frac{3}{2}

= \frac{2}{3} + \frac{3}{2}

Add and subtract (left to right)

\frac{2}{3} + \frac{3}{2} : \frac{13}{6}

= \frac{13}{6}

Convert improper fractions to mixed numbers:

\frac{13}{6} = 2 \frac{1}{6}

= 2 \frac{1}{6}

7 (35 + 59) + 2 (43 - 28)

1 + (5^{2} - 8)

(4 \times 2)^{4}

- (- 3)^{2} - 2

- (- 3)^{2} + 3