What is 3^2*2^3-(-7)^2-(-3)(-5) ?

The solution to 3^2*2^3-(-7)^2-(-3)(-5) is 8

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3^2*2^3-(-7)^2-(-3)(-5)

3^{2} \cdot 2^{3} - (- 7)^{2} - (- 3) (- 5)

8

Solution steps

3^{2} \cdot 2^{3} - (- 7)^{2} - (- 3) (- 5)

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 \cdot 2^{3} - (- 7)^{2} - (- 3) (- 5)

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 9 \cdot 8 - (- 7)^{2} - (- 3) (- 5)

Calculate exponents

(- 7)^{2} : 49

(- 7)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 7)^{2} = 7^{2} = 49

= 49

= 9 \cdot 8 - 49 - (- 3) (- 5)

Multiply and divide (left to right)

9 \cdot 8 : 72

9 \cdot 8

9 \cdot 8 = 72

= 72

= 72 - 49 - (- 3) (- 5)

Multiply and divide (left to right)

(- 3) (- 5) : 15

(- 3) (- 5)

Apply rule

(- a) \cdot (- b) = a \cdot b

(- 3) (- 5) = 3 \cdot 5 = 15

= 15

= 72 - 49 - 15

Add and subtract (left to right)

72 - 49 - 15 : 8

72 - 49 - 15

72 - 49 = 23

= 23 - 15

23 - 15 = 8

= 8

= 8

8 \times 12 \div (30 - 6)

\frac{2}{8} (- 2) - \frac{5}{2}

2 - 3 + 4 - 9

- [\frac{6}{5} \div \frac{9}{10}]

- 2 + (+ 5)^{2}