The solution to 2-10/3+2 is 2/3

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2-10/3+2

Solution

2 - \frac{10}{3} + 2

\frac{2}{3}

Solution steps

2 - \frac{10}{3} + 2

Follow the PEMDAS order of operations

Add and subtract (left to right)

2 - \frac{10}{3} = - \frac{4}{3}

2 - \frac{10}{3}

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= \frac{2 \cdot 3}{3} - \frac{10}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 - 10}{3}

2 \cdot 3 - 10 = - 4

2 \cdot 3 - 10

Multiply the numbers:

2 \cdot 3 = 6

= 6 - 10

Subtract the numbers:

6 - 10 = - 4

= - 4

= \frac{- 4}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{3}

= - \frac{4}{3} + 2

- \frac{4}{3} + 2 = \frac{2}{3}

- \frac{4}{3} + 2

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= \frac{2 \cdot 3}{3} - \frac{4}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 - 4}{3}

2 \cdot 3 - 4 = 2

2 \cdot 3 - 4

Multiply the numbers:

2 \cdot 3 = 6

= 6 - 4

Subtract the numbers:

6 - 4 = 2

= 2

= \frac{2}{3}

= \frac{2}{3}

- (- 7^{2} + (- 9)^{2})

4 + (7 \times 8) 12

(- 15 - 45) + (- 8 + 5)

+ 3 (1 - 5) + 8

6 (0)^{2} - 11