What is (1+1/2)\times (-2-3/4) ?

The solution to (1+1/2)\times (-2-3/4) is -33/8

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(1+1/2)\times (-2-3/4)

(1 + \frac{1}{2}) \cdot (- 2 - \frac{3}{4})

- \frac{33}{8}

Solution steps

(1 + \frac{1}{2}) (- 2 - \frac{3}{4})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 + \frac{1}{2}) : \frac{3}{2}

1 + \frac{1}{2}

1 + \frac{1}{2} = \frac{3}{2}

1 + \frac{1}{2}

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= \frac{1 \cdot 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 2 + 1}{2}

1 \cdot 2 + 1 = 3

1 \cdot 2 + 1

Multiply the numbers:

1 \cdot 2 = 2

= 2 + 1

Add the numbers:

2 + 1 = 3

= 3

= \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2} (- 2 - \frac{3}{4})

Calculate within parentheses

(- 2 - \frac{3}{4}) : - \frac{11}{4}

- 2 - \frac{3}{4}

- 2 - \frac{3}{4} = - \frac{11}{4}

= - \frac{11}{4}

= \frac{3}{2} (- \frac{11}{4})

Multiply and divide (left to right)

\frac{3}{2} (- \frac{11}{4}) : - \frac{33}{8}

\frac{3}{2} (- \frac{11}{4})

Apply rule

a \cdot (- b) = - a \cdot b

\frac{3}{2} (- \frac{11}{4}) = - \frac{3}{2} \cdot \frac{11}{4}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{3}{2} \cdot \frac{11}{4} = \frac{3 \cdot 11}{2 \cdot 4}

= - \frac{3 \cdot 11}{2 \cdot 4}

Multiply the numbers:

3 \cdot 11 = 33

= - \frac{33}{2 \cdot 4}

Multiply the numbers:

2 \cdot 4 = 8

= - \frac{33}{8}

= - \frac{33}{8}

2^{2} - 3 (2) + 2

- 8 - 2 + 2

(7 + 3 \frac{1}{8}) + (14 + 6 \frac{1}{4})

5^{3} \times 3^{2}

2 (12) + 18

What is (1+1/2)\times (-2-3/4) ?
The solution to (1+1/2)\times (-2-3/4) is -33/8