What is 4/3+20-(1/2 \times (-4)) ?

The solution to 4/3+20-(1/2 \times (-4)) is 23 1/3

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4/3+20-(1/2 \times (-4))

Solution

\frac{4}{3} + 20 - (\frac{1}{2} \cdot (- 4))

Solution

23 \frac{1}{3}

Solution steps

\frac{4}{3} + 20 - (\frac{1}{2} (- 4))

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{1}{2} \cdot (- 4)) : - 2

\frac{1}{2} (- 4)

Multiply and divide (left to right)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{1}{2} (- 4) = - \frac{1}{2} \cdot 4

Convert element to fraction:

4 = \frac{4}{1}

= - \frac{1}{2} \cdot \frac{4}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{1}{2} \cdot \frac{4}{1} = \frac{1 \cdot 4}{2 \cdot 1}

= - \frac{1 \cdot 4}{2 \cdot 1}

\frac{1 \cdot 4}{2 \cdot 1} = 2

\frac{1 \cdot 4}{2 \cdot 1}

\frac{1 \cdot 4}{2 \cdot 1} = \frac{4}{2}

\frac{1 \cdot 4}{2 \cdot 1}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{4}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{4}{2}

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= - 2

= \frac{4}{3} + 20 - (- 2)

Add and subtract (left to right)

\frac{4}{3} + 20 - (- 2) : \frac{70}{3}

\frac{4}{3} + 20 - (- 2)

\frac{4}{3} + 20 = \frac{64}{3}

\frac{4}{3} + 20

Convert element to fraction:

20 = \frac{20 \cdot 3}{3}

= \frac{20 \cdot 3}{3} + \frac{4}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{20 \cdot 3 + 4}{3}

20 \cdot 3 + 4 = 64

20 \cdot 3 + 4

Multiply the numbers:

20 \cdot 3 = 60

= 60 + 4

Add the numbers:

60 + 4 = 64

= 64

= \frac{64}{3}

= \frac{64}{3} - (- 2)

Apply rule

- (- a) = + a

- (- 2) = + 2

= \frac{64}{3} + 2

\frac{64}{3} + 2 = \frac{70}{3}

\frac{64}{3} + 2

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= \frac{2 \cdot 3}{3} + \frac{64}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 + 64}{3}

2 \cdot 3 + 64 = 70

2 \cdot 3 + 64

Multiply the numbers:

2 \cdot 3 = 6

= 6 + 64

Add the numbers:

6 + 64 = 70

= 70

= \frac{70}{3}

= \frac{70}{3}

= \frac{70}{3}

Convert improper fractions to mixed numbers:

\frac{70}{3} = 23 \frac{1}{3}

\frac{70}{3} = 23

Remainder

1

\frac{70}{3}

Write the problem in long division format

3 \overline{∣ 70}

Divide

7

3

to get

2

Divide

7

3

to get

2

2 3 \overline{∣ 70}

Multiply the quotient digit

(2)

by the divisor

3

2 3 \overline{∣ 70} \underline{6}

Subtract

6

from

7

2 3 \overline{∣ 70} \underline{6} 1

Bring down the next number of the dividend

2 3 \overline{∣ 70} \underline{6} 10

2 3 \overline{∣ 70} \underline{6} 10

Divide

10

3

to get

3

Divide

10

3

to get

3

23 3 \overline{∣ 70} \underline{6} 10

Multiply the quotient digit

(3)

by the divisor

3

23 3 \overline{∣ 70} \underline{6} 10 \underline{9}

Subtract

9

from

10

23 3 \overline{∣ 70} \underline{6} 10 \underline{9} 1

23 3 \overline{∣ 70} \underline{6} 10 \underline{9} 1

The solution for Long Division of

\frac{70}{3}

23

with remainder of

1

23 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{70}{3} = 23 \frac{1}{3}

= 23 \frac{1}{3}

= 23 \frac{1}{3}

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Frequently Asked Questions (FAQ)

What is 4/3+20-(1/2 \times (-4)) ?
The solution to 4/3+20-(1/2 \times (-4)) is 23 1/3