What is 9+[40\div (-8)] ?

The solution to 9+[40\div (-8)] is 4

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9+[40\div (-8)]

9 + [40 \div (- 8)]

4

Solution steps

9 + [40 \div (- 8)]

Follow the PEMDAS order of operations

Calculate within parentheses

[40 \div (- 8)] : - 5

40 \div (- 8)

Apply rule

a \div (- b) = - a \div b

40 \div (- 8) = - 40 \div 8 = - 5

= - 5

= 9 - 5

Add and subtract (left to right)

9 - 5 : 4

9 - 5

9 - 5 = 4

= 4

= 4

12 - 24 + 12

2 5^{2} + 6 0^{2}

0^{2} + 110 + 18

4 (2)^{2} + 14 (2) - 2

- 20 \div 4 \times 3 + (12 - 8) \times (- 2)