What is 3(1)^2+6(1)-9 ?

The solution to 3(1)^2+6(1)-9 is 0

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3(1)^2+6(1)-9

3 (1)^{2} + 6 (1) - 9

0

Solution steps

3 (1)^{2} + 6 (1) - 9

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 3 \cdot 1 + 6 (1) - 9

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= 3 + 6 (1) - 9

Multiply and divide (left to right)

6 (1) : 6

6 (1)

Apply rule:

(a) = a

(1) = 1

= 6 \cdot 1

Multiply the numbers:

6 \cdot 1 = 6

= 6

= 3 + 6 - 9

Add and subtract (left to right)

3 + 6 - 9 : 0

3 + 6 - 9

3 + 6 = 9

= 9 - 9

9 - 9 = 0

= 0

= 0

- 1920 + 740 (10)

- (- 22 + 16 - 19) + (17 - 7) - (8 - 28)

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41 + 5 \cdot (- 9) + (63 \div 7 - 4)

(12 \div 4) + 20 - [2 \times 3 - 2] + 4