What is 4(5^2-3^3)^0 ?

The solution to 4(5^2-3^3)^0 is 4

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4(5^2-3^3)^0

4 (5^{2} - 3^{3})^{0}

4

Solution steps

4 (5^{2} - 3^{3})^{0}

Follow the PEMDAS order of operations

Calculate within parentheses

(5^{2} - 3^{3}) : - 2

5^{2} - 3^{3}

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 25 - 3^{3}

Calculate exponents

3^{3} : 27

3^{3}

3^{3} = 27

= 27

= 25 - 27

Add and subtract (left to right)

25 - 27 : - 2

25 - 27

25 - 27 = - 2

= - 2

= - 2

= 4 (- 2)^{0}

Calculate exponents

(- 2)^{0} : 1

(- 2)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{0} = 2^{0} = 1

= 1

= 4 \cdot 1

Multiply and divide (left to right)

4 \cdot 1 : 4

4 \cdot 1

4 \cdot 1 = 4

= 4

= 4

9 - 15 + 2

(65 \frac{5}{11} - 64) \times 16

5 + (- 3) - (- 2) + (4 - 6) - [3 - (6 - 4)]

36 - (- 9)^{2}

3^{4} - 3^{2}