What is 32\times 5+(28\div 7)\div 5\times 71(58-18) ?

The solution to 32\times 5+(28\div 7)\div 5\times 71(58-18) is 2432

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32\times 5+(28\div 7)\div 5\times 71(58-18)

32 \times 5 + (28 \div 7) \div 5 \times 71 (58 - 18)

2432

Solution steps

32 \times 5 + (28 \div 7) \div 5 \times 71 (58 - 18)

Follow the PEMDAS order of operations

Calculate within parentheses

(28 \div 7) : 4

28 \div 7

28 \div 7 = 4

= 4

= 32 \times 5 + 4 \div 5 \times 71 (58 - 18)

Calculate within parentheses

(58 - 18) : 40

58 - 18

58 - 18 = 40

= 40

= 32 \times 5 + 4 \div 5 \times 71 \cdot 40

Multiply and divide (left to right)

32 \times 5 : 160

32 \times 5

32 \times 5 = 160

= 160

= 160 + 4 \div 5 \times 71 \cdot 40

Multiply and divide (left to right)

4 \div 5 \times 71 \cdot 40 : 2272

4 \div 5 \times 71 \cdot 40

4 \div 5 = \frac{4}{5}

= \frac{4}{5} \times 71 \cdot 40

\frac{4}{5} \times 71 = \frac{284}{5}

\frac{4}{5} \cdot 71

Convert element to fraction:

71 = \frac{71}{1}

= \frac{4}{5} \cdot \frac{71}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 71}{5 \cdot 1}

Multiply the numbers:

4 \cdot 71 = 284

= \frac{284}{5 \cdot 1}

Multiply the numbers:

5 \cdot 1 = 5

= \frac{284}{5}

= \frac{284}{5} \cdot 40

\frac{284}{5} 40 = 2272

\frac{284}{5} \cdot 40

Convert element to fraction:

40 = \frac{40}{1}

= \frac{284}{5} \cdot \frac{40}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{284 \cdot 40}{5 \cdot 1}

Cancel

\frac{284 \cdot 40}{5 \cdot 1} : 2272

\frac{284 \cdot 40}{5 \cdot 1}

Multiply the numbers:

5 \cdot 1 = 5

= \frac{284 \cdot 40}{5}

Divide the numbers:

\frac{40}{5} = 8

= 284 \cdot 8

Multiply the numbers:

284 \cdot 8 = 2272

= 2272

= 2272

= 2272

= 160 + 2272

Add and subtract (left to right)

160 + 2272 : 2432

160 + 2272

160 + 2272 = 2432

= 2432

= 2432

30 \div 3 \times (5 - 2)

\frac{13}{16} - (\frac{1}{4} - \frac{3}{8})

(2 \times 3)^{4}

(1 + 2 + 3)^{2}

23 + 1 - 5

What is 32\times 5+(28\div 7)\div 5\times 71(58-18) ?
The solution to 32\times 5+(28\div 7)\div 5\times 71(58-18) is 2432