What is 9\div 3-3(5-6)^2 ?

The solution to 9\div 3-3(5-6)^2 is 0

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9\div 3-3(5-6)^2

9 \div 3 - 3 (5 - 6)^{2}

0

Solution steps

9 \div 3 - 3 (5 - 6)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 6) : - 1

5 - 6

5 - 6 = - 1

= - 1

= 9 \div 3 - 3 (- 1)^{2}

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 9 \div 3 - 3 \cdot 1

Multiply and divide (left to right)

9 \div 3 : 3

9 \div 3

9 \div 3 = 3

= 3

= 3 - 3 \cdot 1

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= 3 - 3

Add and subtract (left to right)

3 - 3 : 0

3 - 3

3 - 3 = 0

= 0

= 0

(- 2)^{4} \div (- 5)^{2}

\frac{2}{( 0 - 1 ) ^{3}}

6 + 1 - 10 - 9 + 8

6 \times 3 + 2 \times 7

(10 \div 2) \times 3 - 3