What is 3{2+5[3+(6-4)^2+1]-7} ?

The solution to 3{2+5[3+(6-4)^2+1]-7} is 105

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3{2+5[3+(6-4)^2+1]-7}

3 {2 + 5 [3 + (6 - 4)^{2} + 1] - 7}

105

Solution steps

3 {2 + 5 [3 + (6 - 4)^{2} + 1] - 7}

Follow the PEMDAS order of operations

Calculate within parentheses

{2 + 5 [3 + (6 - 4)^{2} + 1] - 7} : 35

= 3 \cdot 35

Multiply and divide (left to right)

3 \cdot 35 : 105

= 105

15 + [5 - (6 + 3) - (8 - 2)]

2 \times 3^{2} \times 3 \times 5

15 - 3 \cdot 12 \div 6 + 4^{2} \div 8

\frac{- 6 - 2 ( 1 )}{4}

3 (3)^{2} - 12 (3) + 9